Question

The population of a colony over 10 years is tabulated below :

Year(t)	2000	2005	2010
Population(P)	3000	3700	4000

The saturation population of the colony is :

• A. 4160
• B. 4340
• C. 4470
• D. 4560

Answer 1

The correct option is A 4160

$P_0=3000,t_0=0$
$P_1=3700,t_1=5yrs$
$P_1=4000,t_2=10yrs$
Saturation population, $P_s=\frac{2P_0{P}_1{P}_2-P_1^2(P_0+P_2)}{P_0{P}_2-P_1^2}$
$=\frac{2\times 3000\times 3700\times 4000\times -\left(3700{)}^2\right(3000+4000)}{(3000\times 4000)-(3700{)}^2}$
=$4159.76\approx 4160$