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Question

The population of a particular area of a city is 5000. It increases by 10% in 1st year. It decreases by 20% in the 2nd year because of some reason. In the 3rd year, the population increases by 30%. What will be the population of area at the end of 3 years?

A
5120
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B
5300
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C
5720
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D
5620
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Solution

The correct option is C 5720
Population of a city at the starting of first year =5000
It increases by 10% in 1st year.
i.e., Population at the end of 1st year = Population at the starting of 2nd year
=5000+10% of 5000=5000+10100×5000=5500
It decreases by 20% in 2nd year.
i.e., Population at the end of 2nd year = Population at the starting of 3rd year
=550020% of 5500=550020100×5500=55001100=4400
It increases by 30% in 3rd year.
i.e., Population at the end of 3rd year
=4400+30% of 4400=4400+30100×4400=4400+1320=5720

So, C is the correct option.

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