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Question

The population of a place increased to 54000 in 2003 at a rate of 5% per annum. Its population in 2005 will be P. What is the sum of the digits in P

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Solution

Let p= Initial population =54000, i.e., in the year 2003
Rate of growth =5%
Population after 2 years, i.e., in 2005
P=p(1+R100)n=54000×(1+5100)2
P=54000×105100×105100=59535
sum of digits in P=5+9+5+3+5=27

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