Question

The population of a town in $2009$ was $125000$. It increase $10\%$ per year. What is the population after $3$ years?

• A. $166375$
• B. $170000$
• C. $125000$
• D. $10000$

Answer 1

The correct option is A $166375$

Taking $P$ as the population of the town in $2009$, $n$ is the number of years after which the population is to be calculated and $R$ is the rate at which the population increases, then:

Population after $3$ years $=P{(1+\frac{R}{100})}^n$

$=12500{(1+\frac{10}{100})}^3$

$=12500{(1+\frac{1}{10})}^3$

$=12500{\left(\frac{11}{10}\right)}^3$

$=12500\times \frac{1331}{1000}$

$=16,637.5$