Question

The population of a town increased from $1,75,000$ to $2,62,500$ in a decade. The average percent increase of population per year is:

• A. $4.37$%
• B. $5$%
• C. $6$%
• D. $8.75$%

Answer 1

The correct option is B $5$%

Increase in $10$years $=(262500-175000)=87500$
Increase %$=(\frac{87500}{175000}\times 100)$%$=50$%
$\therefore$ Required average$=\left(\frac{50}{10}\right)$%$=5$%