Question

The population of a town increases by 10.5$\%$ every year. If its present population is 7,95,600, what was it a year ago.

Answer 1

Given that, the population of a town increases by $10.5\%$ every year.

Also, the present population is $7,95,600$.

To find out: Population of the town a year ago.

Let the population of the town a year ago be $x$.

$\therefore \text{Population}1years\text{ago}=\frac{100}{100+increase\%}\times \text{present population}$

$\Rightarrow x=\frac{100}{110.5}\times 795600=720000$

Hence, the population of the town a year ago was $7,20,000$.