Question

The population of a town increases every year at rate of $10\%$. Find the population of the town three years hence if it is $13000$ now.

• A. $17303$
• B. $27303$
• C. $37303$
• D. $47303$

Answer 1

The correct option is A $17303$

Given, $P=13000,r=10\%,n=3$ years
We know, $A=P\left[{(1+\frac{r}{100})}^n\right]$
$\Rightarrow A=13000\left[{(1+\frac{10}{100})}^3\right]$
$\Rightarrow A=17303$
Hence, the population of the town $3$ years is $17303$.