Question

The population of a town increases evry year at rate of $10\%$. The present population of the town is $12,500$. Find the population of the town after $2$ years.

• A. $15125$
• B. $25125$
• C. $35125$
• D. $45125$

Answer 1

The correct option is A $15125$

Given, $P=12500,r=10\%,n=2$ years
We know, $A=P\left[{(1+\frac{r}{100})}^n\right]$
$\Rightarrow A=12500\left[{(1+\frac{10}{100})}^2\right]$
$\Rightarrow A=$ Rs. $15125$
Hence, the population after $2$ years $=15125$.