Question

The population of a town was 1,60,000 three years ago. If it increased by 3%, 2.5% and 5%, respectively, in the last three years, then what is the present population?

• A. 166,366
• B. 177,366
• C. 166,377
• D. 177,377

Answer 1

The correct option is B 177,366

Present population $=1,60,000(1+\frac{3}{100})(1+\frac{2.5}{100})(1+\frac{5}{100})$
$=160000\times \frac{103}{100}\times \frac{102.2}{100}\times \frac{105}{100}=177366$