The population of a town was 3600 three years back. It is 4800 right now. What will be the population three years down the line, if the rate of growth of population has been constant over the years?

3200

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4400

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6000

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7600

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Solution

The correct option is C 6000
The population of the town grew from $3, 600$ to $4, 800$ in three years.
Hence, the growth during this 3 year span = $4, 800$ - $3, 600$ = $1, 200$

The rate of growth of population is given to be constant.
Hence, population growth per year = $1, 200 / 3$ = $400$

Hence, total population after three years
= $4, 800$ + $(400 * 3)$
= $4, 800$ + $1, 200$
= $6, 000$
Hence, C is the correct answer.

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