The population of Albany, New York is about $98, 989$ and the population of Moscow, Russia is about $12, 235, 448$ . Approximately how many times greater is the population of Moscow than the population of Albany?

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Solution

The population of Albany, New York is about $98, 989$ and the population of Moscow, Russia is about $12, 235, 448$ .
To find out how many times greater is the population of Moscow than the population of Albany, we should divide $12, 235, 448$ by $98, 989$ .
$= 12, 235, 448 \div 98, 989$
$= 123.6$
Hence, population of Russia is $123.6$ times greater than population of Moscow.

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