The population of city increases by $30$ every year .If the present population is $33800$ ,then what was the population of the city two years ago?

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Solution

Let population of city two years ago was $x$

So $30 %$ Increase every year.

$(\frac{130}{100}) (\frac{130}{100}) x = 338000$

So $1.3 \times 1.3 x = 338000$

$\Rightarrow x = \frac{338000}{1.3 \times 1.3} = 200000$

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The population of city increases by 30every year .If the present population is 33800,then what was the population of the city two years ago?

Let population of city two years ago was xSo 30% Increase every year.(130100)(130100)x=338000So 1.3×1.3x=338000⇒x=3380001.3×1.3=200000

The population of city increases by $30$ every year .If the present population is $33800$ ,then what was the population of the city two years ago?

Let population of city two years ago was $x$

So $30 %$ Increase every year.

$(\frac{130}{100}) (\frac{130}{100}) x = 338000$

So $1.3 \times 1.3 x = 338000$

$\Rightarrow x = \frac{338000}{1.3 \times 1.3} = 200000$