The population of city was $20, 000$ in the year $1997$ . It increased at the rate of $5 % p . a .$ . Find the population at the end of the year $2000$ .

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Solution

$A = P (\frac{1 + R}{100}) N$

$I n i t i a l p o p u l a t i o n o f t h e c i t y (P) = 20, 000$

$R a t e o f i n c r e a s e (R) = 5$

$N (n u m b e r o f y e a r s) = 3$

$P o p u l a t i o n o f t h e c i t y a f t e r 3 y e a r s = A$

$A = 20000 {(\frac{1 + 5}{1 O O})}^{3}$

$= 20000 {(\frac{1 + 5}{1 O O})}^{3}$

$= \frac{(20000 * 105 * 105 * 105)}{(100 * 100 * 100)}$

$A = 23152.5$

$S o, p o p u l a t i o n o f c i t y a f t e r 3 y e a r s = 23152.5$

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The population of city was 20,000 in the year 1997. It increased at the rate of 5% p.a.. Find the population at the end of the year 2000.

A=P(1+R100)NInitialpopulationofthecity(P)=20,000Rateofincrease(R)=5N(numberofyears)=3Populationofthecityafter3years=AA=20000(1+51OO)3=20000(1+51OO)3=(20000∗105∗105∗105)(100∗100∗100) A=23152.5So,populationofcityafter3years=23152.5

The population of city was $20, 000$ in the year $1997$ . It increased at the rate of $5 % p . a .$ . Find the population at the end of the year $2000$ .