Question

The population of Hyderabad was $68,09,000$ in the year $2011$. If it increases at the rate of $4.7\%perannum$. What will be population at the end of the year $2015$.

Answer 1

Let the population of Hyderabad be $A=68,09,000$ and $r$ be the rate of increase in the population.

If $Z$ is the population of Hyderabad after 4 years, then, by compounding formula,

$Z=A+{\left(1+\frac{r}{100}\right)}^t$

$Z=6809000{\left(1+\frac{4.7}{100}\right)}^4$

$Z=8182199$

Therefore, the population in the year 2015 is 8182199.