Question

The population of Hyderabad was $68,09,000$ in the year $2011$. If it increases at the rate of $4.7\%$ per annum. What will be the population at the end of the year $2015$.

Answer 1

The population of Hydrabad was $6809000$ in the year $2011$.

It increases by $4.7$% per annum.

To calculate population after $4$ years with a given rate of interest.

Using the compounding formula

$Z=A+{\left(1+\frac{r}{100}\right)}^t$

Where $Z$ is Population at the end of duration.

$A$ is present population

$t$ is time perior

$r$ is rate of intrest

We know that $4.7$

Substitute the values,

$Z=6809000+{\left(1+\frac{4.7}{100}\right)}^4$

$Z=6809000{\left(1.047\right)}^4$

$Z=6809000\times 1.2016741717$

$Z=8182199$