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Direction of Instantaneous Velocity

The position ...

Question

The position coordinate of a particle moving along a straight line is given by x = $4 t^{3}$ - $3 t^{2}$ + $4 t$ + $5$ . Then what is velocity at $t = 1$ ?

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Solution

The correct option is A $10$
$v = \frac{d x}{d t}$ .
$V_{t = 1 s e c} = 12 (1)^{2} - 6 (1) + 4$
$V = 10$ .

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