The position coordinates of a projectile projected from ground on a certain planet ( with no atmosphere ) are given by y = (4t - 2t^2) m and x= (3t) metre , where t is in second and point of projection is taken as origin. The angle of projection of projectile with the vertical is ?

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Solution

Velocity can be found by differentiating these terms.
V_y=4-4t
V_x=3
Now, for initial velocity, t=0. So velocity in y would be 4.
We know that V_y/V_x=tan theta.
So, angle=tan^-14/3

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Q. The position coordinates of a projectile projected from ground on a certain planet (with no atmosphere) are given by y =

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The position coordinates of a projectile projected from the ground on a certain planet (with no atmosphere) are given by $y = (4 t - 2 t^{2}) m$ and $x = (3 t)$ meter, where t is in second and point of projection is taken as the origin. The angle of projection of projectile with vertical is