the position of a body is given by X = 18 + 4 bt? where A and B are constants x is position and t is time find acceleration as a function of time

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Dear student,
Though your question is not very much though we are trying to give answer of it.
$X = 18 + 4 b t^{2} \Rightarrow \frac{d X}{d t} = v = 8 b t = V e l o c i t y \Rightarrow \frac{d^{2} X}{d t^{2}} = 8 b = A c c e l e r a t i o n .$

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the position of a body is given by X = 18 + 4 bt? where A and B are constants x is position and t is time find acceleration as a function of time

Dear student, Though your question is not very much though we are trying to give answer of it. X=18+4bt2⇒dXdt=v=8bt=Velocity⇒d2Xdt2=8b=Acceleration. Regrads

Dear student,
Though your question is not very much though we are trying to give answer of it.
$X = 18 + 4 b t^{2} \Rightarrow \frac{d X}{d t} = v = 8 b t = V e l o c i t y \Rightarrow \frac{d^{2} X}{d t^{2}} = 8 b = A c c e l e r a t i o n .$

Regrads