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Standard XII

Physics

Order of Magnitude

The position ...

Question

The position of a body moving along $x -$ axis is given by $x = 3 t - t^{3}$ , where $x$ is in meter and $t$ is in second. Find the acceleration at t=1 .

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Solution

$x = 3 t - t^{3}$
$a = \frac{d^{2} x}{d t^{2}}$
$a = - 6 t$
at t=1
$a = - 6$

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The position of a body moving along x−axis is given by x=3t−t3, where x is in meter and t is in second. Find the acceleration at t=1 .

x=3t−t3a=d2xdt2a=−6tat t=1a=−6

The position of a body moving along $x -$ axis is given by $x = 3 t - t^{3}$ , where $x$ is in meter and $t$ is in second. Find the acceleration at t=1 .

$x = 3 t - t^{3}$
$a = \frac{d^{2} x}{d t^{2}}$
$a = - 6 t$
at t=1
$a = - 6$