The position of a boy moving along a straight line is x=150m with respect to origin (x=0) at 10.30a.m. If he is moving along +vex−axis at a constant speed of 6km/hr, what will be his position at the time 10.45a.m ?
A
750m
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B
1000m
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C
1800m
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D
1650m
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Solution
The correct option is D1650m Initial position of boy is, xi=150m The time interval for journey of boy is, Δt=15minute=14hr Boy is moving at a constant speed, v=6km/hr Hence displacement of boy along +vex−axis is, ⇒Displacement(Δx)=velocity×Δt ⇒Δx=vΔt ⇒Δx=6km/hr×14hr=1.5km ⇒Δx=1.5×1000=1500m Hence new position of boy will be, xf=xi+Δx ⇒xf=150+1500=1650m