The position of a particle is given as r-i-2j-k- and its momentum by p-3i- 4j-2k- The angular momentum is perpendicular to -

The correct option is A x axis Angular momentum is r⃗×p⃗= i amp; j amp; k 1 amp; 2 amp; 1 3 amp; 4 amp; 2 = #16 ...

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Angular Analogue of Linear Momentum

The position ...

Question

The position of a particle is given as $\to r = \to i + 2 \to j - \to k$ and its momentum by $\to p = 3 \to i + 4 \to j - 2 \to k$ . The angular momentum is perpendicular to :

x - a x i s

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y - a x i s

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z - a x i s

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Line at equal angles to all the axes.

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Solution

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\to r = (ˆ i + 2 ˆ j - ˆ k)

\to P = (3 ˆ i + 4 ˆ j - 2 ˆ k)

\to i + 2 \to j - \to k

⊥

\to r . (3 \to i - \to j + \to k) = 1

\to r . (\to i + 4 \to j - 2 \to k) = 2

l_{1} = \to r (t) = (\to i - 6 \to j + 2 \to k) + t (\to i + 2 \to j + \to k)

l_{2} = \to R (u) = (4 \to j + \to k) + u (2 \to i + \to j + 2 \to k)

\to r \cdot (3 \to i - \to j + \to k) = 1

\to r \cdot (3 \to i + 4 \to j - 2 \to k) = 2

\to r =^i + 2^j -^k

\to p = 3^i + 4^j - 2^k

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