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Motion Under Variable Acceleration

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The position of a particle moving along x axis is given by x=At+4Bt3 what is its velocity at t=5s?

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Q. For a body moving along

x -

axis, its velocity is given by

v = \frac{a}{b} (1 - e^{- b t})

a

b

are positive constant. At

t = 0, x = 0

x

of the particle with time

t

Q. A particle starts from the origin at time t = 0 and moves along the positive x - axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

Q. The position of a particle moving along x-axis given by

x = (- 2 t^{3} + 3 t^{2} + 5) m

. The acceleration of particle at the instant its velocity becomes zero is

Q. The initial velocity of a particle moving along

x -

u (a t t = 0 a n d x = 0)

and its acceleration a is given by

a = k x

. Which of the following equation is correct between its velocity

(v)

(x)

?

Q. The position of a particle along along x-axis is given by

x = a + b t^{2}

, where a= 8.5 m, b = 2.5 m and

t

is in seconds. What is its average velocity at t = 2.0 s? What will be its average velocity between

t = 2 s

t = 4 s

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