The position of a particle moving in the x y-plane at any time is given by x-3 t2-6 t metres- y-t2-2 t metres- Select the correct statement about the moving particle from the followingA- The acceleration of the particle is zero at t -0 secondB- The velocity of the particle is zero at t-0 secondC- The velocity of the particle is zero at t-1 secondD- The velocity and acceleration of the particle are never zero

The correct option is C The velocity of the particle is zero at t = 1 secondv_x = dx/dt = d/dt(3t^2 6t) = 6t 6. At t=1, v_x = 0 v_y = dy/dt = d/dt(t^2 2t) = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Motion Under Variable Acceleration

The position ...

Question

The position of a particle moving in the xy-plane at any time is given by $x = (3 t^{2} - 6 t)$ metres, $y = (t^{2} - 2 t)$ metres. Select the correct statement about the moving particle from the following

The acceleration of the particle is zero at t = 0 second

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The velocity of the particle is zero at t = 0 second

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The velocity of the particle is zero at t = 1 second

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The velocity and acceleration of the particle are never zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C The velocity of the particle is zero at t = 1 second
$v_{x} = \frac{d x}{d t} = \frac{d}{d t} (3 t^{2} - 6 t) = 6 t - 6.$ At $t = 1, v_{x} = 0$
$v_{y} = \frac{d y}{d t} = \frac{d}{d t} (t^{2} - 2 t) = 2 t - 2.$ At $t = 1, v_{y} = 0$
Hence $v = \sqrt{v_{x}^{2} + v_{y}^{2}} = 0$

Suggest Corrections

Similar questions

Q. The position of a particle moving in the xy-plane at any time is given by

x = (3 t^{2} - 6 t)

metres,

y = (t^{2} - 2 t)

metres. Select the correct statement about the moving particle from the following

Q. The position of a particle moving in the x-y plane at any time

t

is given by :

x = (3 t^{3} - 6 t)

metres;

y = (t^{2} - 2 t)

metres. Select the correct statement.

Q. A particle moves along a straight line such that its position

x

at any time

t

is given given by.

x = 2 t^{3} - 12 t^{2} + 6 t + 8

The velocity of the particle when its acceleration is zero is (

x

is in metre and

t

is in second)

Q. A particle moves along a straight line such that its displacement at any time

t

is given by

s = t^{3} - 6 t^{2} + 3 t + 4

metres. The velocity when the acceleration is zero is:-

Q. The position of a particle moving in the X-Y plane from origin at any time

t

is given by

x = (3 t^{2} - 6 t)

y = (t^{2} - 2 t)

m, where

t

is in seconds. Select the correct statement(s) about the moving particle from the following.

Join BYJU'S Learning Program

The position of a particle moving in the xy-plane at any time is given by x=(3t2−6t) metres, y=(t2−2t) metres. Select the correct statement about the moving particle from the following

The correct option is C The velocity of the particle is zero at t = 1 secondvx=dxdt=ddt(3t2−6t)=6t−6. At t=1,vx=0 vy=dydt=ddt(t2−2t)=2t−2. At t=1,vy=0 Hence v=√v2x+v2y=0

The position of a particle moving in the xy-plane at any time is given by $x = (3 t^{2} - 6 t)$ metres, $y = (t^{2} - 2 t)$ metres. Select the correct statement about the moving particle from the following