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Differentiation

The position ...

Question

The position of a particle moving on x-axis is given by, $x = A t^{3} + B t^{3} + C t + D$ . The numerical value of $A, B, C, D$ are $1, 4, - 2, 5$ respectively and SI units are used. What is the velocity pf the particle at $t = 4 s$ ?

78 m s^{- 1}

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87 m s^{- 1}

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68 m s^{- 1}

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97 m s^{- 1}

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Solution

The correct option is A $78 m s^{- 1}$
correct option $(A)$

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Similar questions

X

X = A t^{3} + B t^{2} + C t + D .

A, B, C, D

1, 4, - 2

5

t = 0

t = 4 s

X

X = A t^{3} + B t^{2} + C t + D .

A, B, C, D

1, 4, - 2

5

t = 0

t = 4 s

x

x = {A t}^{2} + B t + C

x -

x = {a t}^{3} + {b t}^{2} + c t + d

v = \frac{a}{b} (1 - e^{- b t})

t = 0

x = 0

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