The position of a particle varies with time as r - at 2- tj where -10 ms -2 and -5 ms -1 The torque acting on the particle at t -1 s in N mis- mass of the particle m-0-1 kg A- 5 k-B- -3 k-C- 10 k-D- -10 k-

The correct option is C 10k̂r⃗ = 10t^2 î 5t ĵ v⃗ = dr⃗/dt =20 t î 5 ĵ a⃗ = 20 î F⃗ = m a⃗ = (0.1)(20) î =2î r⃗ = 10 î 5ĵ τ⃗= r̂×F⃗ = (10 î 5ĵ) × 2i⃗ = 1 ...

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Byju's Answer

Standard XII

Physics

Electric Field

The position ...

Question

The position of a particle varies with time as $\to r = a t^{2}^i + β t^j w h e r e α = 10 m s^{- 2} a n d β = 5 m s^{- 1}$ The torque acting on the particle at t = 1s in N m is: (mass of the particle m = 0.1 kg)

5^k

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10^k

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Solution

The correct option is C $10^k$
$\to r = 10 t^{2}^i - 5 t^j$
$\to v = \frac{d \to r}{d t}$
$= 20 t^i - 5^j$
$\to a = 20^i$
$\to F = m \to a$
$= (0.1) (20)^i$
$= 2^i$
$\to r = 10^i - 5^j$
$\to τ =^r \times \to F$
$= (10^i - 5^j) \times 2 \to i$
$= 10^k o p t i o n (c)$

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The position of a particle varies with time as →r=at2^i+βt^j whereα=10ms−2 andβ=5 ms−1 The torque acting on the particle at t = 1s in N m is: (mass of the particle m = 0.1 kg)

The correct option is C 10^k→r=10t2^i−5t^j →v=d→rdt =20 t ^i−5^j →a=20 ^i →F=m →a =(0.1)(20)^i =2^i →r=10^i−5^j →τ=^r×→F =(10^i−5^j)×2→i =10 ^k option (c)

The position of a particle varies with time as $\to r = a t^{2}^i + β t^j w h e r e α = 10 m s^{- 2} a n d β = 5 m s^{- 1}$ The torque acting on the particle at t = 1s in N m is: (mass of the particle m = 0.1 kg)

The correct option is C $10^k$
$\to r = 10 t^{2}^i - 5 t^j$
$\to v = \frac{d \to r}{d t}$
$= 20 t^i - 5^j$
$\to a = 20^i$
$\to F = m \to a$
$= (0.1) (20)^i$
$= 2^i$
$\to r = 10^i - 5^j$
$\to τ =^r \times \to F$
$= (10^i - 5^j) \times 2 \to i$
$= 10^k o p t i o n (c)$