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Question

The position of the particle is given by x=2t34t2+5 in m. The acceleration of the particle at 5 sec is

A
45 m/s2
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B
48 m/s2
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C
40 m/s2
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D
52 m/s2
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Solution

The correct option is D 52 m/s2
As we know that the acceleration of the particle is given by
a=dvdt and also, v=dxdt
Given, x=2t34t2+5
So, v=dxdt=d(2t34t2+5)dt
v=6t28t
also, a=dvdt=d(6t28t)dt=12t8
Thus, the acceleration of the particle is 12×58=52 m/s2

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