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Question

The position of the particle is given by x=3t26t+4 in m. The acceleration of the particle at 10 sec is

A
5 m/s2
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B
6 m/s2
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C
4 m/s2
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D
10 m/s2
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Solution

The correct option is B 6 m/s2
As we know that the acceleration of the particle is given by
a=dvdt and also, v=dxdt
Given, x=3t26t+4
So, v=dxdt=d(3t26t+4)dt
v=6t6
also, a=dvdt=d(6t6)dt=6
Thus, the acceleration of the particle is constant i.e 6 m/s2

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