The position of the particle is given by x=t2+5t+2 in m. The average speed of the particle in 6sec is
A
11m/s
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B
10m/s
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C
13m/s
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D
12m/s
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Solution
The correct option is A11m/s Given, x=t2+5t+2 We know that the average speed is given by (xf−xi)t So, at t=0,xi=0+0+2=2m and, at t=6sec,xf=62+5×6+2=68m Thus, average speed =68−26=11m/s