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Byju's Answer
Standard XIII
Physics
Differentiation
The position ...
Question
The position of the particle is given by
x
(
t
)
=
(
4
t
2
−
3
t
+
2
t
3
)
, its acceleration will be
A
4
t
+
2
t
2
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B
12
t
2
+
8
t
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C
8
t
−
3
+
6
t
2
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D
12
t
+
8
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Solution
The correct option is
D
12
t
+
8
a
=
d
v
d
t
=
d
2
x
d
t
2
=
d
2
(
4
t
2
−
3
t
+
2
t
3
)
d
t
2
=
12
t
+
8
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0
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