The position of the point $(- 8, 9)$ with respect to the lines $2 x + 3 y - 4 = 0$ and $6 x + 9 y + 8 = 0$ is

p o i n t l i e s o n t h e s a m e s i d e o f t h e l i n e s

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Solution

The correct option is B $p o i n t l i e s o n t h e s a m e s i d e o f t h e l i n e s$
Given lines
$2 x + 3 y - 4 = 0$ ------(1)
$6 x + 9 y + 8 = 0$ ------(2)
Point $P (- 8, 9)$
Putting P in eq(1)
$2 (- 8) + 3 (9) - 4 = 0$
$- 16 + 27 - 4 = 0$
$7 > 0$
Now putting P in eq (2)
$- 48 + 91 + 8 = 0$
$51 > 0$
Both have +ve value
Hence point lies on same sides of both lines

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Similar questions

(8, - 9)

2 x + 3 y - 4 = 0

6 x + 9 y + 8 = 0

- 2 x - 3 y + 7 = 0, - 6 x - 9 y + 21 = 0

2 x + 3 y = 10

6 x + 9 y = 11

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