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Question

The position vector of a particle is determined by the expression ¯r = 3 t2 ^i + 4 t2^j + 7^k .The distance traversed in first 10 sec is

A
500 m
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B
300 m
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C
150 m
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D
100 m
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Solution

The correct option is A 500 m
As the particle moves in a straight path, the magnitude of displacement is equal to the distance travelled by the particle
r = 3 t2 ^i + 4 t2^j + 7^k
at t = 0, r1 = 7¯k
at t = 10 sec,r2 = 300 ^i + 400^j + 7 ^k
r = r2 - r1 = 300^i + 400^j
|r| = | r2 - r1| = (300)2+(400)2 = 500m

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