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Question

The position vector of a particle is given by r=1.2t^i+0.9t2^j0.6(t31)^k where t is the time in seconds from the start of motion and where r is expressed in metres.
Determine the power (P=F.v) in watts produced by the force F=(60^i25^j40^k)N which is acting on the particle at time t=4 seconds.

A
1044W
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B
10.44W
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C
2088W
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D
20.88W
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Solution

The correct option is A 1044W

v=drdt=1.2^i+1.8t^j1.8t2^k

At t=4s,v=1.2^i+7.2^j28.8^k

P=F.v=(60^i25^j40^k)(1.2^i+7.2^j28.8^k)

=1044W


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