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Question

The position vector of a particle of mass m=6kg is given as r=[(3t26t)^i+(4t3)^j]m. Find
(i) the force (F=ma) acting on the particle.
(ii) the torque (τ=r×F) with respect to the origin, acting on the particle.
(iii) the momentum (p=mv) of the particle.
(iv) the angular momentum (L=r×p) of the particle with respect to the origin.

A
(i)(36^i144t^j)N (ii)(288t3+864t2)^k (iii)(36t36)^i72t2^j (iv)(72t4+288t3)^k
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B
(i)(63^i144t^j)N (ii)(288t3+864t2)^k (iii)(36t36)^i72t2^j (iv)(72t4+288t3)^k
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C
(i)(36^i144t^j)N (ii)(28t3+84t2)^k (iii)(36t36)^i72t2^j (iv)(72t4+288t3)^k
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D
(i)(36^i144t^j)N (ii)(288t3+864t2)^k (iii)(3t6)^i72t2^j (iv)(72t4+288t3)^k
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Solution

The correct option is A (i)(36^i144t^j)N (ii)(288t3+864t2)^k (iii)(36t36)^i72t2^j (iv)(72t4+288t3)^k

v=drdt=(6t6)^i+(12t2)^jm/s

a=dvdt=(6^i24t^j)m/s2

(i)F=ma=6(6^i24t^j)=(36^i144t^j)N

(ii)τ=r×F=[(3t26t)^i+(4t3)^j]×[36^i144t^j]

=[(144×3t2)+(144×6T2)+144t3]^k

=(288t3+864t2)^k

(iii)p=mv=6[(6t6)^i+(12t2)^j]

=[36(t1)^i72t2t2^j]

(iv)L=r×p=[(3t26t)^i+(4t3)^j]×[36(t1)^i72t2^j]

=[72t4+288t3]^k


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