The position vector of a point P is r - x - y - z k- when x - y - z - N and a -k- - If r - a -10- the number of possible position of P isA- 72B- 36C- 66D- 9 C2

The correct option is B 36 r̅.a̅=10 ⇒ x + y + z =10, x, y, z ϵ N no. of solutions = ^10 1C_3 1=36 ...

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Standard XII

Mathematics

Modulus of a Complex Number

The position ...

Question

The position vector of a point P is $\to r = x^i + y^j + z^k$ , when $x, y, z ϵ$ N and $\to a =^i +^j +^k . I f \to r . \to a = 10$ , the number of possible position of P is

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Solution

The correct option is A
36

$¯ r . ¯ a = 10$
$\Rightarrow x + y + z = 10, x, y, z ϵ N$
no. of solutions = $^{10 - 1} C_{3 - 1} = 36$

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The position vector of a point P is →r=x^i+y^j+z^k, when x,y,zϵ N and →a=^i+^j+^k.If→r.→a=10, the number of possible position of P is

The correct option is A 36 ¯r.¯a=10 ⇒x+y+z=10,x,y,zϵN no. of solutions = 10−1C3−1=36

The position vector of a point P is $\to r = x^i + y^j + z^k$ , when $x, y, z ϵ$ N and $\to a =^i +^j +^k . I f \to r . \to a = 10$ , the number of possible position of P is

The correct option is A
36

$¯ r . ¯ a = 10$
$\Rightarrow x + y + z = 10, x, y, z ϵ N$
no. of solutions = $^{10 - 1} C_{3 - 1} = 36$