Division and Distribution into Groups of Unequal Sizes
The position ...
Question
The position vector of a point P is →r=x→i+y→j+z→k where x and y are positive integers and →a=→i+→j+→k If →r.→a=10, then the number of possible positions of P is :
A
48
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B
72
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C
24
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D
36
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Solution
The correct option is D 36 →r.→a=x+y+z ∴x+y+z=10where x and y are positive integers. ∴No. of positive integral solutions of X+y+z=10is(10−1)C3−1=9C2=36.