The correct option is A 425
We know that if the projectile is projected at an angle θ with the horizontal.
x−component of displacement is given by
sx=ucosθt
and y−component is given by
sy=usinθt−12gt2
So, →s=(ucosθ)t^i+((usinθ)t−12gt2)^j
Comparing →r and →s
ucosθ=3 and usinθ=4
∴u2cos2θ+u2sin2θ=32+42
⇒u2=25⇒u=5 m/s
and ucosθ=3
⇒cosθ=35, sinθ=45
Now, Hmax=u2sin2θ2g
∴ Required ratio =Hmaxu=usin2θ2g
=5(45)22×10=165×20=425