The position vector of P is 4 -3 - and the position vector of Q is -2 -5 - The vector 2 PQ is A- -6 -2 -B- -12 -4 -C- 12 -4 -D- 6 -2 -

The correct option is B 12î+4ĵSince, the position vector is taken from origin O. So, we have PQ=OQ OP ⇒ PQ=( 2î+5ĵ) (4î+3ĵ)= 6î+2ĵ Thus, 2PQ= 2( 6î+2ĵ)= 12î+4 ...

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Standard XII

Physics

Introduction

The position ...

Question

The position vector of $P$ is $4^i + 3^j$ and the position vector of $Q$ is $- 2^i + 5^j$ . The vector $2 - - \to P Q$ is

- 6^i + 2^j

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- 12^i + 4^j

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12^i - 4^j

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6^i - 2^j

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Solution

The correct option is B $- 12^i + 4^j$
Since, the position vector is taken from origin $O$ . So, we have
$- - \to P Q = - - \to O Q - - - \to O P$
$\Rightarrow - - \to P Q = (- 2^i + 5^j) - (4^i + 3^j) = - 6^i + 2^j$
Thus, $2 - - \to P Q = 2 (- 6^i + 2^j) = - 12^i + 4^j$

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Similar questions

Q. The position vector of

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The position vector of P is 4^i+3^j and the position vector of Q is −2^i+5^j. The vector 2−−→PQ is

The correct option is B −12^i+4^jSince, the position vector is taken from origin O. So, we have −−→PQ=−−→OQ−−−→OP ⇒ −−→PQ=(−2^i+5^j)−(4^i+3^j)=−6^i+2^j Thus, 2−−→PQ=2(−6^i+2^j)=−12^i+4^j

The position vector of $P$ is $4^i + 3^j$ and the position vector of $Q$ is $- 2^i + 5^j$ . The vector $2 - - \to P Q$ is

The correct option is B $- 12^i + 4^j$
Since, the position vector is taken from origin $O$ . So, we have
$- - \to P Q = - - \to O Q - - - \to O P$
$\Rightarrow - - \to P Q = (- 2^i + 5^j) - (4^i + 3^j) = - 6^i + 2^j$
Thus, $2 - - \to P Q = 2 (- 6^i + 2^j) = - 12^i + 4^j$