The position vectors of the points A,B,C are ¯i+2¯j−¯¯¯k,¯i+¯j+¯¯¯k,2¯i+3¯j+2¯¯¯k respectively. If A is chosen as the origin then the position vectors of B and C are
A
¯i+2¯¯¯k,¯i+¯j+3¯¯¯k
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B
¯j+2¯¯¯k,→i+¯j+3¯¯¯k
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C
−¯j+2¯¯¯k,→i−¯j+3¯¯¯k
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D
−¯j+2¯¯¯k,¯i+¯j+3¯¯¯k
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Solution
The correct option is C−¯j+2¯¯¯k,¯i+¯j+3¯¯¯k The origin is shifted so the new position vectors of B and C would be the difference of the old position vectors and the new origin vector i.e.
(i+j+k)−(i+2j−k)=−j+2k ( New position vector of point B)
(2i+3j+2k)−(i+2j−k)=i+j+3k( New position vector of point A)