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Question

The position vectors of two identical particles with respect to the origin in three-dimensional coordinate system are r1 and r2. The position vector of centre of mass of the system is given by:

A
r1+r2
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B
2(r1+r2)
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C
r1r2
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D
r1+r22
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E
r1+r23
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Solution

The correct option is D r1+r22
Given, position vector of first particle=r1
Position vector of second particle=r2
m1=m2=m
We know that,
Position of centre of mass of system
R=m1r1+m2r2m1+m2
R=mr1+mr2m+m
R=m(r1+r2)2m=r1+r22.

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