We are given the values of time, but the values of the position are to obtained from the graph corresponding to the given time interval under consideration. We know that the slope of the displacement-time graph represents velocity.
We have, vav=x2−x1t2−t1
a. Here x1=0m,x2=10m;t1=0s,t2=2s.
Therefore, the required average velocity is given by
vav=10−02−0 = 5 m/s
b. Here x1=10m,x2=5m;t1=2s,t2=4s.
So the required value of average velocity is given by
vav=5−104−2 = -2.5 m/s
c. Here x1=5m,x2=−5m;t1=4s,t2=7s.
So the required value of average velocity is given by
vav=−5−57−4 = -3.3 m/s