The position of a body moving along the x-axis at time t is given by $t^{2} - 4 t + 6$ . The distance traveled by body in time interval t= 0 to t = 3 s is

The position of a body moving along x-axis at t is given by x=(t²-4t+6)m. The distance travelled by body in time interval t=0 to t=3 s is
(A) 5m
(B) 7m
(C) 4m
(D) 3m

Q. The displacement x of a body having relation with time as

x = 3 t^{2} - 6 t + 7

, then distance covered by body in first two second is [where x is in metre and t is in second]

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The position (x) of a body is changing with time (t) as x=t2−4t−2. Find the distance covered by body in 4 s (where x is an meters and t is in seconds).

The correct option is D ZeroThe position of the body is given by t2−4t−2 Position of the body at 0 sec =0×0−4×0−2=−2 Position of the body at 4 sec =4×4−4×4−2=−2 Therefore, distance =−2−(−2)=0.

The position (x) of a body is changing with time (t) as $x = t^{2} - 4 t - 2$ . Find the distance covered by body in 4 s (where x is an meters and t is in seconds).

The correct option is D Zero
The position of the body is given by $t^{2} - 4 t - 2$
Position of the body at 0 sec $= 0 \times 0 - 4 \times 0 - 2 = - 2$
Position of the body at 4 sec $= 4 \times 4 - 4 \times 4 - 2 = - 2$
Therefore, distance $= - 2 - (- 2) = 0$ .