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Byju's Answer
Standard XII
Physics
Vectors and Its Types
the position ...
Question
the position (x) of a particle moving along x-axis varies with time (t) as x=t^{2 - 4t +5. The particle turns around at time?
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Q.
The position of a particle moving along the
x
-axis varies with time
t
as
x
=
4
t
−
t
2
+
1
. Find the time interval(s) during which the particle is moving along positive
x
- direction.
Q.
The position of a particle moving along x-axis varies with time
t
as
x
=
4
t
−
t
2
+
1
. If the time interval(s) during which the particle is moving along positive x-direction is
0
<
t
<
u
. The value of
u
(in
s
) is
Q.
The position of a particle moving along x-axis varies with time
t
as
x
=
4
t
−
t
2
+
1
. If the time interval(s) during which the particle is moving along positive x-direction is
0
<
t
<
u
. The value of
u
(in
s
) is
Q.
The position x of a particle moving along x-axis varies with time t as x=Again(ωt) where A and ω are positive constants. The acceleration of a particle varies with its position (x) as
Q.
The position x of particle moving along x- axis varies with time t as x= A sin
(
ω
t
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where A and
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are positive constants. The acceleration a of particle varies with its position (x) as
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