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Spring Force

The position ...

Question

The position $x$ of a particle varies with time $t$ a $a t^{2} - b t^{3}$ . The acceleration of particle will be zero at time $t$ is equal to

\frac{a}{b}

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\frac{2 a}{3 b}

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\frac{a}{3 b}

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zero

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Solution

The correct option is C $\frac{a}{3 b}$
$\begin{matrix} x = a t^{2} - b t^{3} v = 2 a t - 3 b t^{2} a = 2 a - 6 b t = 0 t = \frac{a}{3 b} H e n c e, o p t i o n C i s c o r r e c t a n s w e r . \end{matrix}$

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