The positive numbers x and y satisfy xy = 1. Then the value of x such thatis minimum.

is a rational number

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is an irrational number

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is greater than two

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is 2.

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Solution

The correct option is B
is an irrational number

As xy = 1 or x = 1/y, we have

Hence the minimum value required is 1 and is got when

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Similar questions

The positive numbers x and y satisfy xy = 1. Then the value of x such thatis minimum.

x

y

x y = 1.

x + y

x + y + z = 3

\frac{1}{x} + \frac{1}{y} + \frac{1}{z}

= 1.

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