The positive value of K for which the equation x2-k x-64-0 has equal roots is -A- 16B- -16C- -8D- 8

The correct option is A 16x2 + kx + 64 = 0 Here a = 1, b = k and c = 64 To have equal roots b2 – 4ac = 0 Therefore, (k)2 – 4 1 64 = 0 k2 – 256 = 0 k2 = 256 k ...

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Standard X

Mathematics

Nature of Roots

The positive ...

Question

The positive value of K for which the equation x² + kx + 64 = 0 has equal roots is :

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Solution

The correct option is
A

16

x² + kx + 64 = 0
Here a = 1, b = k and c = 64
To have equal roots
b² – 4ac = 0
Therefore, (k)² – 4 (1) 64 = 0
k² – 256 = 0
k² = 256
k = 16
k = 16 is the positive value of k.

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The positive value of K for which the equation x2 + kx + 64 = 0 has equal roots is :

The correct option is A 16x2 + kx + 64 = 0 Here a = 1, b = k and c = 64 To have equal roots b2 – 4ac = 0 Therefore, (k)2 – 4 (1) 64 = 0 k2 – 256 = 0 k2 = 256 k = 16 k = 16 is the positive value of k.

The positive value of K for which the equation x² + kx + 64 = 0 has equal roots is :

The correct option is
A

16

x² + kx + 64 = 0
Here a = 1, b = k and c = 64
To have equal roots
b² – 4ac = 0
Therefore, (k)² – 4 (1) 64 = 0
k² – 256 = 0
k² = 256
k = 16
k = 16 is the positive value of k.