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Byju's Answer
Standard XII
Mathematics
Pair of Lines Passing Though Origin
The positive ...
Question
The positive value of parameter '
a
' for which the area bounded by parabolas
y
=
x
−
a
x
2
&
a
y
=
x
2
attains its the maximum value is
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Solution
On solving, we get
x
=
0
,
a
a
2
+
1
Required area
=
∫
λ
/
1
+
λ
2
0
(
x
−
a
x
2
−
x
2
a
)
d
x
Δ
′
=
a
(
1
−
a
)
(
1
+
a
)
(
1
+
a
2
)
3
⇒
a
=
1
gives maximum.
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