The positon vectors of the points A-B-C are -2-k- -k- 2-3-2k- respectively- If A is chosen as the origin then the position vectors of B and C are-

The correct option is D ĵ+2k̂, î+ĵ+3k̂ AB= ĵ+2k̂ AC= î+ĵ+3k̂ If A is origin #160; B= ĵ+2k̂ C= î+ĵ+3k̂ ...

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Cross Product of Two Vectors

The positon v...

Question

The positon vectors of the points $A, B, C$ are $^i + 2^j -^k$ , $^i +^j +^k, 2^i + 3^j + 2^k$ respectively. If $A$ is chosen as the origin then the position vectors of $B$ and $C$ are:

^j + 2^k,^i +^j + 3^k

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^j + 2^k,^i +^j + 3^k

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-^j + 2^k,^i -^j + 3^k

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-^j + 2^k,^i +^j + 3^k

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Find $\to a . (\to b \times \to c)$ , if $\to a = 2^i +^j + 3^k, \to b = -^i + 2^j +^k$ and $\to c = 3^i +^j + 2^k$ .

\to a . (\to b \times \to c)

\to a = 2^i +^j + 3^k, \to b = -^i + 2^j +^k a n d \to c = 3^i +^j + 2^k

a = -^i +^j + 2^k

b = 2^i -^j -^k

c = - 2^i +^j + 3^k

(^i +^j - 3^k), (^i + 3^j - 2^k)

(2^i +^j + 4^k)

0, 5, 8

^i +^j - 3^k

^i + 3^j - 2^k

2^i +^j + 4 k

0, 5

8

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