Question

The possible energy value(s) of the excited state(s) for electrons in Bohr's first orbit of hydrogen is/are:

• A. $-3.4eV$
• B. $-4.2eV$
• C. $-6.8eV$
• D. $+6.8eV$

Answer 1

The correct option is A $-3.4eV$

The energy of an electron in the first Bohr orbit of H-atom is $-$13.6eV. The possible energy value of the excited state for electrons in Bohr orbits of hydrogen is $-3.4$ eV.
$E=-\frac{13.6}{n^2}$ eV
When $n=1$, $E=-\frac{13.6}{1^2}=-13.6$ eV.
When $n=2$, $E=-\frac{13.6}{2^2}=-3.4$ eV.
When $n=3$, $E=-\frac{13.6}{3^2}=-1.51$ eV.
When $n=4$, $E=-\frac{13.6}{4^2}=-0.85$ eV.
When $n=5$, $E=-\frac{13.6}{5^2}=-0.544$ eV.