Question

The possible number of electrons for which n = 4, $l$ = 3 and s = +$\frac{1}{2}$ is:

• A. 7
• B. 5
• C. 10
• D. 14

Answer 1

The correct option is A 7

Each electron has a distinct set of quantum numbers in an atom.
For n = 4 and $l$ = 3,
Maximum possible orbitals $=2l+1=(2\times 3)+1=7$.
These orbitals have 14 electrons in total; 7 electrons with s = $+\frac{1}{2}$ and 7 electrons with s = $-\frac{1}{2}$.