The possible number of geometrical isomers for the complex $[P t (N H_{3}) (N H_{2} O H) (N O_{2}) (p y)] N O_{2}$ are:

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Solution

The correct option is A 3
Square planar complex of the type $[M A X B L]^{n +}$ (where A, B, X, and L are unidentate ligands) shows two cis and one trans isomer as shown in the image.

$[P t (N H_{3}) (N H_{2} O H) (N O_{2}) (p y)] N O_{2}$ is a square plannar complex. Thus three geometrical isomer(s) is possible in it.

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=

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